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Need help with an ASCII hack (Loop) https://www.kodewerx.org/forum/viewtopic.php?f=5&t=6562 |
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Author: | h2o-drache [ Wed Feb 25, 2009 8:07 am ] |
Post subject: | Need help with an ASCII hack (Loop) |
Hello I wanted to make a hack so when you push the "/"-Button (0x2f in hex) the output on your screen is a NEW LINE (0x0a in hex). the game is metroid prime hunters eu 1.0 here. Code: there are more values that i found: 2259be8 beginning of string 2147E54 at the moment entered symbol 2149348 length of the string you entered and here is the code i want to have in a loop, but i dont know how to do this so i need your help plz ![]() Code: 92259be8 0000002f
22259be8 0000000a D0000000 00000000 92259be9 0000002f 22259be9 0000000a D0000000 00000000 92259bea 0000002f 22259bea 0000000a D0000000 00000000 92259beb 0000002f 22259beb 0000000a D0000000 00000000 92259bec 0000002f 22259bec 0000000a D0000000 00000000 92259bed 0000002f 22259bed 0000000a D0000000 00000000 92259bee 0000002f 22259bee 0000000a D0000000 00000000 92259bef 0000002f 22259bef 0000000a D0000000 00000000 92259bf0 0000002f 22259bf0 0000000a D0000000 00000000 92259bf1 0000002f 22259bf1 0000000a D0000000 00000000 92259bf2 0000002f 22259bf2 0000000a D0000000 00000000 92259bf3 0000002f 22259bf3 0000000a D0000000 00000000 92259bf4 0000002f 22259bf4 0000000a D0000000 00000000 92259bf5 0000002f 22259bf5 0000000a D0000000 00000000 92259bf5 0000002f 22259bf5 0000000a D0000000 00000000 92259bf6 0000002f 22259bf6 0000000a D0000000 00000000 92259bf7 0000002f 22259bf7 0000000a D0000000 00000000 92259bf8 0000002f 22259bf8 0000000a D0000000 00000000 92259bf9 0000002f 22259bf9 0000000a D0000000 00000000 92259bfa 0000002f 22259bfa 0000000a D0000000 00000000 92259bfb 0000002f 22259bfb 0000000a D0000000 00000000 92259bfc 0000002f 22259bfc 0000000a D0000000 00000000 92259bfd 0000002f 22259bfd 0000000a D0000000 00000000 92259bfe 0000002f 22259bfe 0000000a D0000000 00000000 92259bff 0000002f 22259bff 0000000a D0000000 00000000 92259c00 0000002f 22259c00 0000000a D0000000 00000000 ... |
Author: | RxZ95sssPG [ Wed Feb 25, 2009 8:46 am ] |
Post subject: | Re: Need help with an ASCII hack (Loop) |
0x02147E54 = last added char? mabye so: 92147E54 FFFF002f // if last char == / 22147E54 0000000a // then last char = \n D0000000 00000000 Loop: d5000000 0000000a // stored = 0x0000000a c0000000 0000000a // Repeat 10 times // { d8000000 22259be8 // (0x22259be8 + offset++) = stored d2000000 00000000 // } End-repeat |
Author: | h2o-drache [ Wed Feb 25, 2009 10:45 am ] |
Post subject: | Re: Need help with an ASCII hack (Loop) |
Quote: 0x02147E54 = last added char? yes it saves the last added symbol or char. Do you mean it this way??? Code: 023FE26C E1D320B0 // Offset Support for the if 9 023FE270 E1E03004 d5000000 0000000a // stored = 0x0000000a c0000000 0000000a // Repeat 10 times // { 92259be8 FFFF002f // if string current position == / (2147E54 i dont like this adress because when im deleting sth it dont saves 0x00 it saves only symbols and 0x20...) d8000000 22259be8 // then last char = \n D0000000 00000000 // (0x22259be8 + offset++) = stored // } d2000000 00000000 // End-repeat 023FE26C E1D320B0 // NO Offset Support for the if 9 023FE270 E1E03004 or did i made sth wrong? |
Author: | RxZ95sssPG [ Thu Feb 26, 2009 5:33 am ] |
Post subject: | Re: Need help with an ASCII hack (Loop) |
yeah its right (Conditional Code Adresses are not changed by the offset register) |
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